5p^2=-p

Solution for 5p^2=-p equation:

5p^2=-p

We move all terms to the left:

5p^2-(-p)=0

We add all the numbers together, and all the variables

5p^2-(-1p)=0

We get rid of parentheses

5p^2+1p=0

We add all the numbers together, and all the variables

5p^2+p=0

a = 5; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·5·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*5}=\frac{-2}{10}
=-1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*5}=\frac{0}{10}
=0
$